(50x)^2=10

Solution for (50x)^2=10 equation:

(50x)^2=10

We move all terms to the left:

(50x)^2-(10)=0

a = 50; b = 0; c = -10;
Δ = b2-4ac
Δ = 02-4·50·(-10)
Δ = 2000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{2000}=\sqrt{400*5}=\sqrt{400}*\sqrt{5}=20\sqrt{5}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-20\sqrt{5}}{2*50}=\frac{0-20\sqrt{5}}{100}
=-\frac{20\sqrt{5}}{100}
=-\frac{\sqrt{5}}{5}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+20\sqrt{5}}{2*50}=\frac{0+20\sqrt{5}}{100}
=\frac{20\sqrt{5}}{100}
=\frac{\sqrt{5}}{5}
$